The winning Connecticut Play4 numbers for January 26, 2003 were: night 9-2-0-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jan 26, 2003 | Night | 9-2-0-5 | 16 | 7 |
| Jan 25, 2003 | Night | 5-4-5-1 | 15 | 6 |
| Jan 24, 2003 | Night | 2-5-7-4 | 18 | 9 |
| Jan 24, 2003 | Day | 5-8-7-2 | 22 | 4 |
| Jan 23, 2003 | Night | 1-7-0-8 | 16 | 7 |
| Jan 23, 2003 | Day | 2-8-6-2 | 18 | 9 |
| Jan 22, 2003 | Night | 4-4-9-1 | 18 | 9 |
| Jan 22, 2003 | Day | 9-5-9-4 | 27 | 9 |
| Jan 21, 2003 | Night | 1-9-3-1 | 14 | 5 |
| Jan 21, 2003 | Day | 8-7-8-4 | 27 | 9 |
| Jan 20, 2003 | Night | 2-6-1-9 | 18 | 9 |
| Jan 20, 2003 | Day | 2-0-0-6 | 8 | 8 |