The winning Connecticut Play4 numbers for January 19, 2003 were: night 9-8-6-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jan 19, 2003 | Night | 9-8-6-4 | 27 | 9 |
| Jan 18, 2003 | Night | 4-6-8-7 | 25 | 7 |
| Jan 17, 2003 | Night | 3-1-6-1 | 11 | 2 |
| Jan 17, 2003 | Day | 6-2-5-1 | 14 | 5 |
| Jan 16, 2003 | Night | 0-1-0-0 | 1 | 1 |
| Jan 16, 2003 | Day | 2-0-7-3 | 12 | 3 |
| Jan 15, 2003 | Night | 5-4-8-8 | 25 | 7 |
| Jan 15, 2003 | Day | 7-8-2-9 | 26 | 8 |
| Jan 14, 2003 | Night | 2-7-2-8 | 19 | 1 |
| Jan 14, 2003 | Day | 4-6-2-4 | 16 | 7 |
| Jan 13, 2003 | Night | 2-1-6-7 | 16 | 7 |
| Jan 13, 2003 | Day | 4-2-7-2 | 15 | 6 |