The winning Connecticut Play4 numbers for January 4, 2003 were: night 4-3-4-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jan 4, 2003 | Night | 4-3-4-1 | 12 | 3 |
| Jan 3, 2003 | Night | 0-1-5-2 | 8 | 8 |
| Jan 3, 2003 | Day | 5-9-7-2 | 23 | 5 |
| Jan 2, 2003 | Night | 7-9-3-5 | 24 | 6 |
| Jan 2, 2003 | Day | 4-1-6-6 | 17 | 8 |
| Jan 1, 2003 | Night | 3-9-3-9 | 24 | 6 |
| Jan 1, 2003 | Day | 6-6-0-9 | 21 | 3 |
| Dec 31, 2002 | Night | 8-6-9-8 | 31 | 4 |
| Dec 31, 2002 | Day | 1-5-2-3 | 11 | 2 |
| Dec 30, 2002 | Night | 7-9-2-0 | 18 | 9 |
| Dec 30, 2002 | Day | 6-0-9-0 | 15 | 6 |
| Dec 29, 2002 | Night | 2-5-0-7 | 14 | 5 |