The winning Connecticut Play4 numbers for December 28, 2002 were: night 8-0-2-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 28, 2002 | Night | 8-0-2-1 | 11 | 2 |
| Dec 27, 2002 | Night | 7-2-8-3 | 20 | 2 |
| Dec 27, 2002 | Day | 1-7-3-1 | 12 | 3 |
| Dec 26, 2002 | Night | 6-5-4-2 | 17 | 8 |
| Dec 26, 2002 | Day | 0-2-6-3 | 11 | 2 |
| Dec 25, 2002 | Night | 8-9-8-5 | 30 | 3 |
| Dec 25, 2002 | Day | 7-9-5-4 | 25 | 7 |
| Dec 24, 2002 | Night | 0-7-2-8 | 17 | 8 |
| Dec 24, 2002 | Day | 8-9-0-6 | 23 | 5 |
| Dec 23, 2002 | Night | 4-8-8-6 | 26 | 8 |
| Dec 23, 2002 | Day | 5-1-9-1 | 16 | 7 |
| Dec 22, 2002 | Night | 5-1-9-4 | 19 | 1 |