The winning Connecticut Play4 numbers for December 21, 2002 were: night 4-3-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 21, 2002 | Night | 4-3-7-0 | 14 | 5 |
| Dec 20, 2002 | Night | 2-2-4-0 | 8 | 8 |
| Dec 20, 2002 | Day | 4-5-7-6 | 22 | 4 |
| Dec 19, 2002 | Night | 3-6-8-4 | 21 | 3 |
| Dec 19, 2002 | Day | 3-9-2-3 | 17 | 8 |
| Dec 18, 2002 | Night | 8-1-3-9 | 21 | 3 |
| Dec 18, 2002 | Day | 7-9-5-5 | 26 | 8 |
| Dec 17, 2002 | Night | 0-2-3-7 | 12 | 3 |
| Dec 17, 2002 | Day | 2-1-9-4 | 16 | 7 |
| Dec 16, 2002 | Night | 4-4-1-3 | 12 | 3 |
| Dec 16, 2002 | Day | 5-9-5-3 | 22 | 4 |
| Dec 15, 2002 | Night | 5-8-5-4 | 22 | 4 |