The winning Connecticut Play4 numbers for December 2, 2002 were: day 5-0-8-0; night 3-8-7-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 2, 2002 | Night | 3-8-7-1 | 19 | 1 |
| Dec 2, 2002 | Day | 5-0-8-0 | 13 | 4 |
| Dec 1, 2002 | Night | 2-3-3-2 | 10 | 1 |
| Nov 30, 2002 | Night | 4-8-1-1 | 14 | 5 |
| Nov 29, 2002 | Night | 5-5-4-4 | 18 | 9 |
| Nov 29, 2002 | Day | 0-5-8-3 | 16 | 7 |
| Nov 28, 2002 | Night | 4-4-4-5 | 17 | 8 |
| Nov 28, 2002 | Day | 0-4-9-5 | 18 | 9 |
| Nov 27, 2002 | Night | 3-7-4-7 | 21 | 3 |
| Nov 27, 2002 | Day | 5-2-3-6 | 16 | 7 |
| Nov 26, 2002 | Night | 5-0-1-5 | 11 | 2 |
| Nov 26, 2002 | Day | 3-0-1-8 | 12 | 3 |