The winning Connecticut Play4 numbers for November 17, 2002 were: night 8-7-0-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 17, 2002 | Night | 8-7-0-2 | 17 | 8 |
| Nov 16, 2002 | Night | 2-6-7-1 | 16 | 7 |
| Nov 15, 2002 | Night | 5-4-7-8 | 24 | 6 |
| Nov 15, 2002 | Day | 3-5-0-9 | 17 | 8 |
| Nov 14, 2002 | Night | 2-7-4-8 | 21 | 3 |
| Nov 14, 2002 | Day | 6-6-7-9 | 28 | 1 |
| Nov 13, 2002 | Night | 9-6-2-5 | 22 | 4 |
| Nov 13, 2002 | Day | 9-4-5-0 | 18 | 9 |
| Nov 12, 2002 | Night | 5-4-7-8 | 24 | 6 |
| Nov 12, 2002 | Day | 9-7-4-9 | 29 | 2 |
| Nov 11, 2002 | Night | 3-7-9-7 | 26 | 8 |
| Nov 11, 2002 | Day | 1-6-1-2 | 10 | 1 |