The winning Connecticut Play4 numbers for October 28, 2002 were: day 1-9-6-1; night 6-6-1-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 28, 2002 | Night | 6-6-1-3 | 16 | 7 |
| Oct 28, 2002 | Day | 1-9-6-1 | 17 | 8 |
| Oct 27, 2002 | Night | 2-9-9-9 | 29 | 2 |
| Oct 26, 2002 | Night | 3-5-1-8 | 17 | 8 |
| Oct 25, 2002 | Night | 4-1-5-4 | 14 | 5 |
| Oct 25, 2002 | Day | 3-4-4-6 | 17 | 8 |
| Oct 24, 2002 | Night | 0-6-8-2 | 16 | 7 |
| Oct 24, 2002 | Day | 2-0-4-1 | 7 | 7 |
| Oct 23, 2002 | Night | 6-8-7-1 | 22 | 4 |
| Oct 23, 2002 | Day | 0-6-8-8 | 22 | 4 |
| Oct 22, 2002 | Night | 8-2-1-2 | 13 | 4 |
| Oct 22, 2002 | Day | 9-0-1-2 | 12 | 3 |