The winning Connecticut Play4 numbers for October 23, 2002 were: day 0-6-8-8; night 6-8-7-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 23, 2002 | Night | 6-8-7-1 | 22 | 4 |
| Oct 23, 2002 | Day | 0-6-8-8 | 22 | 4 |
| Oct 22, 2002 | Night | 8-2-1-2 | 13 | 4 |
| Oct 22, 2002 | Day | 9-0-1-2 | 12 | 3 |
| Oct 21, 2002 | Night | 2-3-6-6 | 17 | 8 |
| Oct 21, 2002 | Day | 1-7-9-5 | 22 | 4 |
| Oct 20, 2002 | Night | 5-9-2-5 | 21 | 3 |
| Oct 19, 2002 | Night | 9-5-2-7 | 23 | 5 |
| Oct 18, 2002 | Night | 6-2-9-9 | 26 | 8 |
| Oct 18, 2002 | Day | 3-4-7-9 | 23 | 5 |
| Oct 17, 2002 | Night | 2-1-3-3 | 9 | 9 |
| Oct 17, 2002 | Day | 5-4-6-4 | 19 | 1 |