The winning Connecticut Play4 numbers for October 19, 2002 were: night 9-5-2-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 19, 2002 | Night | 9-5-2-7 | 23 | 5 |
| Oct 18, 2002 | Night | 6-2-9-9 | 26 | 8 |
| Oct 18, 2002 | Day | 3-4-7-9 | 23 | 5 |
| Oct 17, 2002 | Night | 2-1-3-3 | 9 | 9 |
| Oct 17, 2002 | Day | 5-4-6-4 | 19 | 1 |
| Oct 16, 2002 | Night | 3-4-6-3 | 16 | 7 |
| Oct 16, 2002 | Day | 8-2-6-1 | 17 | 8 |
| Oct 15, 2002 | Night | 1-4-7-5 | 17 | 8 |
| Oct 15, 2002 | Day | 6-4-3-0 | 13 | 4 |
| Oct 14, 2002 | Night | 5-8-6-9 | 28 | 1 |
| Oct 14, 2002 | Day | 3-2-4-3 | 12 | 3 |
| Oct 13, 2002 | Night | 0-4-3-6 | 13 | 4 |