The winning Connecticut Play4 numbers for September 18, 2002 were: day 3-2-0-0; night 1-6-1-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 18, 2002 | Night | 1-6-1-4 | 12 | 3 |
| Sep 18, 2002 | Day | 3-2-0-0 | 5 | 5 |
| Sep 17, 2002 | Night | 4-7-7-2 | 20 | 2 |
| Sep 17, 2002 | Day | 9-2-6-0 | 17 | 8 |
| Sep 16, 2002 | Night | 8-6-8-4 | 26 | 8 |
| Sep 16, 2002 | Day | 6-4-7-1 | 18 | 9 |
| Sep 15, 2002 | Night | 2-3-1-1 | 7 | 7 |
| Sep 14, 2002 | Night | 2-0-3-1 | 6 | 6 |
| Sep 13, 2002 | Night | 4-6-4-1 | 15 | 6 |
| Sep 13, 2002 | Day | 0-0-7-0 | 7 | 7 |
| Sep 12, 2002 | Night | 3-3-4-3 | 13 | 4 |
| Sep 12, 2002 | Day | 7-8-1-3 | 19 | 1 |