The winning Connecticut Play4 numbers for September 14, 2002 were: night 2-0-3-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 14, 2002 | Night | 2-0-3-1 | 6 | 6 |
| Sep 13, 2002 | Night | 4-6-4-1 | 15 | 6 |
| Sep 13, 2002 | Day | 0-0-7-0 | 7 | 7 |
| Sep 12, 2002 | Night | 3-3-4-3 | 13 | 4 |
| Sep 12, 2002 | Day | 7-8-1-3 | 19 | 1 |
| Sep 11, 2002 | Night | 4-9-4-4 | 21 | 3 |
| Sep 11, 2002 | Day | 5-0-4-6 | 15 | 6 |
| Sep 10, 2002 | Night | 4-7-7-5 | 23 | 5 |
| Sep 10, 2002 | Day | 8-3-6-2 | 19 | 1 |
| Sep 9, 2002 | Night | 2-6-2-5 | 15 | 6 |
| Sep 9, 2002 | Day | 6-9-7-4 | 26 | 8 |
| Sep 8, 2002 | Night | 9-7-5-8 | 29 | 2 |