The winning Connecticut Play4 numbers for September 10, 2002 were: day 8-3-6-2; night 4-7-7-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 10, 2002 | Night | 4-7-7-5 | 23 | 5 |
| Sep 10, 2002 | Day | 8-3-6-2 | 19 | 1 |
| Sep 9, 2002 | Night | 2-6-2-5 | 15 | 6 |
| Sep 9, 2002 | Day | 6-9-7-4 | 26 | 8 |
| Sep 8, 2002 | Night | 9-7-5-8 | 29 | 2 |
| Sep 7, 2002 | Night | 9-7-7-0 | 23 | 5 |
| Sep 6, 2002 | Night | 8-3-9-5 | 25 | 7 |
| Sep 6, 2002 | Day | 4-0-8-1 | 13 | 4 |
| Sep 5, 2002 | Night | 2-6-0-3 | 11 | 2 |
| Sep 5, 2002 | Day | 9-2-7-3 | 21 | 3 |
| Sep 4, 2002 | Night | 2-1-7-1 | 11 | 2 |
| Sep 4, 2002 | Day | 3-0-2-5 | 10 | 1 |