The winning Connecticut Play4 numbers for September 8, 2002 were: night 9-7-5-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 8, 2002 | Night | 9-7-5-8 | 29 | 2 |
| Sep 7, 2002 | Night | 9-7-7-0 | 23 | 5 |
| Sep 6, 2002 | Night | 8-3-9-5 | 25 | 7 |
| Sep 6, 2002 | Day | 4-0-8-1 | 13 | 4 |
| Sep 5, 2002 | Night | 2-6-0-3 | 11 | 2 |
| Sep 5, 2002 | Day | 9-2-7-3 | 21 | 3 |
| Sep 4, 2002 | Night | 2-1-7-1 | 11 | 2 |
| Sep 4, 2002 | Day | 3-0-2-5 | 10 | 1 |
| Sep 3, 2002 | Night | 3-4-4-7 | 18 | 9 |
| Sep 3, 2002 | Day | 8-9-6-5 | 28 | 1 |
| Sep 2, 2002 | Night | 3-3-5-0 | 11 | 2 |
| Sep 2, 2002 | Day | 4-5-5-8 | 22 | 4 |