The winning Connecticut Play4 numbers for September 1, 2002 were: night 0-0-3-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 1, 2002 | Night | 0-0-3-1 | 4 | 4 |
| Aug 31, 2002 | Night | 3-2-7-0 | 12 | 3 |
| Aug 30, 2002 | Night | 1-7-1-1 | 10 | 1 |
| Aug 30, 2002 | Day | 8-8-3-7 | 26 | 8 |
| Aug 29, 2002 | Night | 8-4-2-9 | 23 | 5 |
| Aug 29, 2002 | Day | 2-4-2-0 | 8 | 8 |
| Aug 28, 2002 | Night | 6-2-5-3 | 16 | 7 |
| Aug 28, 2002 | Day | 0-6-4-9 | 19 | 1 |
| Aug 27, 2002 | Night | 7-1-9-5 | 22 | 4 |
| Aug 27, 2002 | Day | 3-9-9-1 | 22 | 4 |
| Aug 26, 2002 | Night | 0-2-1-9 | 12 | 3 |
| Aug 26, 2002 | Day | 1-1-0-1 | 3 | 3 |