The winning Connecticut Play4 numbers for August 24, 2002 were: night 9-8-0-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 24, 2002 | Night | 9-8-0-7 | 24 | 6 |
| Aug 23, 2002 | Night | 0-6-7-0 | 13 | 4 |
| Aug 23, 2002 | Day | 4-8-7-7 | 26 | 8 |
| Aug 22, 2002 | Night | 6-6-4-1 | 17 | 8 |
| Aug 22, 2002 | Day | 9-4-1-9 | 23 | 5 |
| Aug 21, 2002 | Night | 5-4-7-2 | 18 | 9 |
| Aug 21, 2002 | Day | 2-4-1-3 | 10 | 1 |
| Aug 20, 2002 | Night | 1-2-8-0 | 11 | 2 |
| Aug 20, 2002 | Day | 8-3-0-6 | 17 | 8 |
| Aug 19, 2002 | Night | 3-2-1-9 | 15 | 6 |
| Aug 19, 2002 | Day | 5-0-3-1 | 9 | 9 |
| Aug 18, 2002 | Night | 2-3-7-2 | 14 | 5 |