The winning Connecticut Play4 numbers for August 12, 2002 were: day 0-1-9-0; night 5-9-5-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 12, 2002 | Night | 5-9-5-2 | 21 | 3 |
| Aug 12, 2002 | Day | 0-1-9-0 | 10 | 1 |
| Aug 11, 2002 | Night | 8-1-2-1 | 12 | 3 |
| Aug 10, 2002 | Night | 7-4-7-5 | 23 | 5 |
| Aug 9, 2002 | Night | 2-6-9-2 | 19 | 1 |
| Aug 9, 2002 | Day | 4-0-4-5 | 13 | 4 |
| Aug 8, 2002 | Night | 2-2-7-8 | 19 | 1 |
| Aug 8, 2002 | Day | 1-9-1-2 | 13 | 4 |
| Aug 7, 2002 | Night | 6-3-4-7 | 20 | 2 |
| Aug 7, 2002 | Day | 3-2-4-5 | 14 | 5 |
| Aug 6, 2002 | Night | 1-3-7-2 | 13 | 4 |
| Aug 6, 2002 | Day | 6-8-0-4 | 18 | 9 |