The winning Connecticut Play4 numbers for August 6, 2002 were: day 6-8-0-4; night 1-3-7-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 6, 2002 | Night | 1-3-7-2 | 13 | 4 |
| Aug 6, 2002 | Day | 6-8-0-4 | 18 | 9 |
| Aug 5, 2002 | Night | 9-4-6-0 | 19 | 1 |
| Aug 5, 2002 | Day | 8-5-5-6 | 24 | 6 |
| Aug 4, 2002 | Night | 1-6-9-7 | 23 | 5 |
| Aug 3, 2002 | Night | 2-3-3-3 | 11 | 2 |
| Aug 2, 2002 | Night | 7-3-1-1 | 12 | 3 |
| Aug 2, 2002 | Day | 8-1-2-1 | 12 | 3 |
| Aug 1, 2002 | Night | 0-3-5-2 | 10 | 1 |
| Aug 1, 2002 | Day | 7-6-4-6 | 23 | 5 |
| Jul 31, 2002 | Night | 0-2-2-7 | 11 | 2 |
| Jul 31, 2002 | Day | 6-1-3-6 | 16 | 7 |