The winning Connecticut Play4 numbers for July 17, 2002 were: day 1-6-1-0; night 4-5-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 17, 2002 | Night | 4-5-7-0 | 16 | 7 |
| Jul 17, 2002 | Day | 1-6-1-0 | 8 | 8 |
| Jul 16, 2002 | Night | 8-9-1-4 | 22 | 4 |
| Jul 16, 2002 | Day | 9-8-0-3 | 20 | 2 |
| Jul 15, 2002 | Night | 1-8-6-8 | 23 | 5 |
| Jul 15, 2002 | Day | 1-1-0-9 | 11 | 2 |
| Jul 14, 2002 | Night | 7-6-7-6 | 26 | 8 |
| Jul 13, 2002 | Night | 1-3-1-3 | 8 | 8 |
| Jul 12, 2002 | Night | 2-2-3-6 | 13 | 4 |
| Jul 12, 2002 | Day | 5-5-9-3 | 22 | 4 |
| Jul 11, 2002 | Night | 0-0-0-1 | 1 | 1 |
| Jul 11, 2002 | Day | 0-5-8-0 | 13 | 4 |