The winning Connecticut Play4 numbers for July 9, 2002 were: day 7-4-7-3; night 1-2-3-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 9, 2002 | Night | 1-2-3-4 | 10 | 1 |
| Jul 9, 2002 | Day | 7-4-7-3 | 21 | 3 |
| Jul 8, 2002 | Night | 1-3-6-5 | 15 | 6 |
| Jul 8, 2002 | Day | 8-0-7-5 | 20 | 2 |
| Jul 7, 2002 | Night | 1-9-3-0 | 13 | 4 |
| Jul 6, 2002 | Night | 0-4-2-0 | 6 | 6 |
| Jul 5, 2002 | Night | 0-7-1-8 | 16 | 7 |
| Jul 5, 2002 | Day | 3-6-5-0 | 14 | 5 |
| Jul 4, 2002 | Night | 5-8-5-6 | 24 | 6 |
| Jul 4, 2002 | Day | 7-2-0-6 | 15 | 6 |
| Jul 3, 2002 | Night | 6-0-8-4 | 18 | 9 |
| Jul 3, 2002 | Day | 4-8-9-5 | 26 | 8 |