The winning Connecticut Play4 numbers for July 5, 2002 were: day 3-6-5-0; night 0-7-1-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 5, 2002 | Night | 0-7-1-8 | 16 | 7 |
| Jul 5, 2002 | Day | 3-6-5-0 | 14 | 5 |
| Jul 4, 2002 | Night | 5-8-5-6 | 24 | 6 |
| Jul 4, 2002 | Day | 7-2-0-6 | 15 | 6 |
| Jul 3, 2002 | Night | 6-0-8-4 | 18 | 9 |
| Jul 3, 2002 | Day | 4-8-9-5 | 26 | 8 |
| Jul 2, 2002 | Night | 3-1-2-0 | 6 | 6 |
| Jul 2, 2002 | Day | 6-0-5-0 | 11 | 2 |
| Jul 1, 2002 | Night | 2-3-9-5 | 19 | 1 |
| Jul 1, 2002 | Day | 8-5-6-6 | 25 | 7 |
| Jun 30, 2002 | Night | 6-9-9-3 | 27 | 9 |
| Jun 29, 2002 | Night | 2-2-6-0 | 10 | 1 |