The winning Connecticut Play4 numbers for May 18, 2002 were: night 7-3-1-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| May 18, 2002 | Night | 7-3-1-6 | 17 | 8 |
| May 17, 2002 | Night | 1-3-4-7 | 15 | 6 |
| May 17, 2002 | Day | 7-7-9-0 | 23 | 5 |
| May 16, 2002 | Night | 0-5-6-8 | 19 | 1 |
| May 16, 2002 | Day | 0-9-2-2 | 13 | 4 |
| May 15, 2002 | Night | 4-4-8-2 | 18 | 9 |
| May 15, 2002 | Day | 2-2-7-1 | 12 | 3 |
| May 14, 2002 | Night | 9-9-2-6 | 26 | 8 |
| May 14, 2002 | Day | 7-0-8-8 | 23 | 5 |
| May 13, 2002 | Night | 6-7-7-4 | 24 | 6 |
| May 13, 2002 | Day | 8-3-2-4 | 17 | 8 |
| May 12, 2002 | Night | 0-7-8-1 | 16 | 7 |