The winning Connecticut Play4 numbers for May 7, 2002 were: day 4-8-0-6; night 5-6-0-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| May 7, 2002 | Night | 5-6-0-0 | 11 | 2 |
| May 7, 2002 | Day | 4-8-0-6 | 18 | 9 |
| May 6, 2002 | Night | 6-4-0-5 | 15 | 6 |
| May 6, 2002 | Day | 2-3-5-8 | 18 | 9 |
| May 5, 2002 | Night | 0-5-2-5 | 12 | 3 |
| May 4, 2002 | Night | 1-4-2-3 | 10 | 1 |
| May 3, 2002 | Night | 4-8-3-3 | 18 | 9 |
| May 3, 2002 | Day | 7-0-6-4 | 17 | 8 |
| May 2, 2002 | Night | 1-1-6-4 | 12 | 3 |
| May 2, 2002 | Day | 9-0-0-1 | 10 | 1 |
| May 1, 2002 | Night | 4-1-6-9 | 20 | 2 |
| May 1, 2002 | Day | 2-3-1-2 | 8 | 8 |