The winning Connecticut Play4 numbers for April 13, 2002 were: night 3-7-8-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Apr 13, 2002 | Night | 3-7-8-6 | 24 | 6 |
| Apr 12, 2002 | Night | 9-0-6-2 | 17 | 8 |
| Apr 12, 2002 | Day | 5-9-9-6 | 29 | 2 |
| Apr 11, 2002 | Night | 9-1-9-7 | 26 | 8 |
| Apr 11, 2002 | Day | 8-9-6-2 | 25 | 7 |
| Apr 10, 2002 | Night | 6-7-0-4 | 17 | 8 |
| Apr 10, 2002 | Day | 3-9-2-9 | 23 | 5 |
| Apr 9, 2002 | Night | 0-7-2-8 | 17 | 8 |
| Apr 9, 2002 | Day | 0-4-1-5 | 10 | 1 |
| Apr 8, 2002 | Night | 9-1-0-0 | 10 | 1 |
| Apr 8, 2002 | Day | 0-9-0-5 | 14 | 5 |
| Apr 7, 2002 | Night | 0-2-4-7 | 13 | 4 |