The winning Connecticut Play4 numbers for March 18, 2002 were: day 7-3-6-3; night 0-6-8-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 18, 2002 | Night | 0-6-8-7 | 21 | 3 |
| Mar 18, 2002 | Day | 7-3-6-3 | 19 | 1 |
| Mar 17, 2002 | Night | 5-5-2-7 | 19 | 1 |
| Mar 16, 2002 | Night | 3-1-1-6 | 11 | 2 |
| Mar 15, 2002 | Night | 8-3-1-6 | 18 | 9 |
| Mar 15, 2002 | Day | 7-3-4-0 | 14 | 5 |
| Mar 14, 2002 | Night | 0-2-2-1 | 5 | 5 |
| Mar 14, 2002 | Day | 1-2-0-2 | 5 | 5 |
| Mar 13, 2002 | Night | 1-2-0-1 | 4 | 4 |
| Mar 13, 2002 | Day | 2-7-8-3 | 20 | 2 |
| Mar 12, 2002 | Night | 1-8-7-1 | 17 | 8 |
| Mar 12, 2002 | Day | 9-6-9-1 | 25 | 7 |