The winning Connecticut Play4 numbers for March 11, 2002 were: day 8-0-4-0; night 7-4-2-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 11, 2002 | Night | 7-4-2-9 | 22 | 4 |
| Mar 11, 2002 | Day | 8-0-4-0 | 12 | 3 |
| Mar 10, 2002 | Night | 8-1-7-8 | 24 | 6 |
| Mar 9, 2002 | Night | 6-8-4-5 | 23 | 5 |
| Mar 8, 2002 | Night | 0-7-5-9 | 21 | 3 |
| Mar 8, 2002 | Day | 7-3-2-4 | 16 | 7 |
| Mar 7, 2002 | Night | 9-0-7-5 | 21 | 3 |
| Mar 7, 2002 | Day | 7-7-4-1 | 19 | 1 |
| Mar 6, 2002 | Night | 2-4-9-6 | 21 | 3 |
| Mar 6, 2002 | Day | 4-4-4-4 | 16 | 7 |
| Mar 5, 2002 | Night | 2-0-8-5 | 15 | 6 |
| Mar 5, 2002 | Day | 5-7-6-4 | 22 | 4 |