The winning Connecticut Play4 numbers for March 7, 2002 were: day 7-7-4-1; night 9-0-7-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 7, 2002 | Night | 9-0-7-5 | 21 | 3 |
| Mar 7, 2002 | Day | 7-7-4-1 | 19 | 1 |
| Mar 6, 2002 | Night | 2-4-9-6 | 21 | 3 |
| Mar 6, 2002 | Day | 4-4-4-4 | 16 | 7 |
| Mar 5, 2002 | Night | 2-0-8-5 | 15 | 6 |
| Mar 5, 2002 | Day | 5-7-6-4 | 22 | 4 |
| Mar 4, 2002 | Night | 3-3-0-1 | 7 | 7 |
| Mar 4, 2002 | Day | 9-3-3-7 | 22 | 4 |
| Mar 3, 2002 | Night | 1-2-0-9 | 12 | 3 |
| Mar 2, 2002 | Night | 5-3-8-9 | 25 | 7 |
| Mar 1, 2002 | Night | 8-2-7-3 | 20 | 2 |
| Mar 1, 2002 | Day | 2-7-3-1 | 13 | 4 |