The winning Connecticut Play4 numbers for December 17, 2000 were: night 1-1-5-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 17, 2000 | Night | 1-1-5-1 | 8 | 8 |
| Dec 16, 2000 | Night | 4-4-0-1 | 9 | 9 |
| Dec 15, 2000 | Night | 0-1-4-4 | 9 | 9 |
| Dec 15, 2000 | Day | 7-9-3-3 | 22 | 4 |
| Dec 14, 2000 | Night | 2-9-7-7 | 25 | 7 |
| Dec 14, 2000 | Day | 1-1-1-2 | 5 | 5 |
| Dec 13, 2000 | Night | 7-1-1-8 | 17 | 8 |
| Dec 13, 2000 | Day | 4-7-9-3 | 23 | 5 |
| Dec 12, 2000 | Night | 3-0-2-3 | 8 | 8 |
| Dec 12, 2000 | Day | 7-8-8-2 | 25 | 7 |
| Dec 11, 2000 | Night | 5-5-7-5 | 22 | 4 |
| Dec 11, 2000 | Day | 5-5-9-4 | 23 | 5 |