The winning Connecticut Play4 numbers for December 2, 2000 were: night 9-4-0-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 2, 2000 | Night | 9-4-0-6 | 19 | 1 |
| Dec 1, 2000 | Night | 3-5-1-2 | 11 | 2 |
| Dec 1, 2000 | Day | 9-5-0-8 | 22 | 4 |
| Nov 30, 2000 | Night | 6-6-6-7 | 25 | 7 |
| Nov 30, 2000 | Day | 4-5-8-0 | 17 | 8 |
| Nov 29, 2000 | Night | 3-7-5-9 | 24 | 6 |
| Nov 29, 2000 | Day | 8-9-5-6 | 28 | 1 |
| Nov 28, 2000 | Night | 8-4-6-8 | 26 | 8 |
| Nov 28, 2000 | Day | 1-8-3-2 | 14 | 5 |
| Nov 27, 2000 | Night | 7-8-1-0 | 16 | 7 |
| Nov 27, 2000 | Day | 1-0-8-4 | 13 | 4 |
| Nov 26, 2000 | Night | 4-2-7-7 | 20 | 2 |