The winning Connecticut Play4 numbers for October 27, 2000 were: day 5-8-5-5; night 8-0-7-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 27, 2000 | Night | 8-0-7-2 | 17 | 8 |
| Oct 27, 2000 | Day | 5-8-5-5 | 23 | 5 |
| Oct 26, 2000 | Night | 2-8-9-1 | 20 | 2 |
| Oct 26, 2000 | Day | 6-0-0-7 | 13 | 4 |
| Oct 25, 2000 | Night | 4-4-5-6 | 19 | 1 |
| Oct 25, 2000 | Day | 9-1-1-0 | 11 | 2 |
| Oct 24, 2000 | Night | 6-3-4-8 | 21 | 3 |
| Oct 24, 2000 | Day | 7-4-4-1 | 16 | 7 |
| Oct 23, 2000 | Night | 3-7-9-4 | 23 | 5 |
| Oct 23, 2000 | Day | 0-7-0-5 | 12 | 3 |
| Oct 22, 2000 | Night | 3-1-4-7 | 15 | 6 |
| Oct 21, 2000 | Night | 0-2-8-0 | 10 | 1 |