The winning Connecticut Play4 numbers for October 18, 2000 were: day 7-8-8-4; night 9-1-4-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 18, 2000 | Night | 9-1-4-9 | 23 | 5 |
| Oct 18, 2000 | Day | 7-8-8-4 | 27 | 9 |
| Oct 17, 2000 | Night | 5-1-5-2 | 13 | 4 |
| Oct 17, 2000 | Day | 5-3-1-1 | 10 | 1 |
| Oct 16, 2000 | Night | 6-9-2-3 | 20 | 2 |
| Oct 16, 2000 | Day | 4-7-2-9 | 22 | 4 |
| Oct 15, 2000 | Night | 0-6-2-9 | 17 | 8 |
| Oct 14, 2000 | Night | 7-9-7-4 | 27 | 9 |
| Oct 13, 2000 | Night | 6-7-3-2 | 18 | 9 |
| Oct 13, 2000 | Day | 8-7-4-5 | 24 | 6 |
| Oct 12, 2000 | Night | 6-2-3-5 | 16 | 7 |
| Oct 12, 2000 | Day | 5-9-8-5 | 27 | 9 |