The winning Connecticut Play4 numbers for October 9, 2000 were: day 6-0-1-8; night 0-3-2-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 9, 2000 | Night | 0-3-2-5 | 10 | 1 |
| Oct 9, 2000 | Day | 6-0-1-8 | 15 | 6 |
| Oct 8, 2000 | Night | 3-7-6-1 | 17 | 8 |
| Oct 7, 2000 | Night | 5-8-7-6 | 26 | 8 |
| Oct 6, 2000 | Night | 3-2-9-6 | 20 | 2 |
| Oct 6, 2000 | Day | 7-3-6-1 | 17 | 8 |
| Oct 5, 2000 | Night | 4-7-5-5 | 21 | 3 |
| Oct 5, 2000 | Day | 1-2-3-0 | 6 | 6 |
| Oct 4, 2000 | Night | 0-2-3-2 | 7 | 7 |
| Oct 4, 2000 | Day | 5-2-9-9 | 25 | 7 |
| Oct 3, 2000 | Night | 1-7-0-5 | 13 | 4 |
| Oct 3, 2000 | Day | 9-1-4-2 | 16 | 7 |