The winning Connecticut Play4 numbers for October 5, 2000 were: day 1-2-3-0; night 4-7-5-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 5, 2000 | Night | 4-7-5-5 | 21 | 3 |
| Oct 5, 2000 | Day | 1-2-3-0 | 6 | 6 |
| Oct 4, 2000 | Night | 0-2-3-2 | 7 | 7 |
| Oct 4, 2000 | Day | 5-2-9-9 | 25 | 7 |
| Oct 3, 2000 | Night | 1-7-0-5 | 13 | 4 |
| Oct 3, 2000 | Day | 9-1-4-2 | 16 | 7 |
| Oct 2, 2000 | Night | 0-1-1-0 | 2 | 2 |
| Oct 2, 2000 | Day | 1-6-4-2 | 13 | 4 |
| Oct 1, 2000 | Night | 6-8-1-9 | 24 | 6 |
| Sep 30, 2000 | Night | 6-7-1-8 | 22 | 4 |
| Sep 29, 2000 | Night | 8-4-5-6 | 23 | 5 |
| Sep 29, 2000 | Day | 8-1-3-8 | 20 | 2 |