The winning Connecticut Play4 numbers for September 10, 2000 were: night 9-3-3-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 10, 2000 | Night | 9-3-3-3 | 18 | 9 |
| Sep 9, 2000 | Night | 8-8-3-4 | 23 | 5 |
| Sep 8, 2000 | Night | 9-4-2-0 | 15 | 6 |
| Sep 8, 2000 | Day | 9-0-4-1 | 14 | 5 |
| Sep 7, 2000 | Night | 5-3-9-3 | 20 | 2 |
| Sep 7, 2000 | Day | 6-1-9-4 | 20 | 2 |
| Sep 6, 2000 | Night | 2-6-0-0 | 8 | 8 |
| Sep 6, 2000 | Day | 4-3-9-0 | 16 | 7 |
| Sep 5, 2000 | Night | 0-4-1-8 | 13 | 4 |
| Sep 5, 2000 | Day | 5-2-8-9 | 24 | 6 |
| Sep 4, 2000 | Night | 9-6-9-4 | 28 | 1 |
| Sep 4, 2000 | Day | 0-6-5-7 | 18 | 9 |