The winning Connecticut Play3 numbers for December 7, 2019 were: day 5-2-3; night 6-5-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 7, 2019 | Night | 6-5-1 | 12 | 3 |
| Dec 7, 2019 | Day | 5-2-3 | 10 | 1 |
| Dec 6, 2019 | Night | 2-2-0 | 4 | 4 |
| Dec 6, 2019 | Day | 2-1-1 | 4 | 4 |
| Dec 5, 2019 | Night | 1-9-9 | 19 | 1 |
| Dec 5, 2019 | Day | 0-5-9 | 14 | 5 |
| Dec 4, 2019 | Night | 4-2-0 | 6 | 6 |
| Dec 4, 2019 | Day | 0-5-2 | 7 | 7 |
| Dec 3, 2019 | Night | 0-5-9 | 14 | 5 |
| Dec 3, 2019 | Day | 2-0-8 | 10 | 1 |
| Dec 2, 2019 | Night | 5-7-3 | 15 | 6 |
| Dec 2, 2019 | Day | 8-0-0 | 8 | 8 |
| Dec 1, 2019 | Night | 1-4-1 | 6 | 6 |
| Dec 1, 2019 | Day | 5-8-2 | 15 | 6 |