The winning Connecticut Play3 numbers for October 4, 2009 were: day 5-9-3; night 0-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 4, 2009 | Night | 0-7-0 | 7 | 7 |
| Oct 4, 2009 | Day | 5-9-3 | 17 | 8 |
| Oct 3, 2009 | Night | 7-2-4 | 13 | 4 |
| Oct 3, 2009 | Day | 1-4-0 | 5 | 5 |
| Oct 2, 2009 | Night | 1-1-7 | 9 | 9 |
| Oct 2, 2009 | Day | 9-3-6 | 18 | 9 |
| Oct 1, 2009 | Night | 2-2-3 | 7 | 7 |
| Oct 1, 2009 | Day | 0-0-0 | 0 | 0 |
| Sep 30, 2009 | Night | 5-7-6 | 18 | 9 |
| Sep 30, 2009 | Day | 2-4-7 | 13 | 4 |
| Sep 29, 2009 | Night | 2-9-2 | 13 | 4 |
| Sep 29, 2009 | Day | 2-5-6 | 13 | 4 |
| Sep 28, 2009 | Night | 9-6-3 | 18 | 9 |
| Sep 28, 2009 | Day | 0-6-8 | 14 | 5 |