The winning Connecticut Play3 numbers for October 12, 2007 were: day 9-8-3; night 8-4-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 12, 2007 | Night | 8-4-6 | 18 | 9 |
| Oct 12, 2007 | Day | 9-8-3 | 20 | 2 |
| Oct 11, 2007 | Night | 7-2-4 | 13 | 4 |
| Oct 11, 2007 | Day | 2-4-1 | 7 | 7 |
| Oct 10, 2007 | Night | 8-6-8 | 22 | 4 |
| Oct 10, 2007 | Day | 6-7-5 | 18 | 9 |
| Oct 9, 2007 | Night | 4-9-3 | 16 | 7 |
| Oct 9, 2007 | Day | 9-4-4 | 17 | 8 |
| Oct 8, 2007 | Night | 2-4-3 | 9 | 9 |
| Oct 8, 2007 | Day | 3-6-4 | 13 | 4 |
| Oct 7, 2007 | Night | 7-7-8 | 22 | 4 |
| Oct 7, 2007 | Day | 1-2-6 | 9 | 9 |
| Oct 6, 2007 | Night | 1-8-8 | 17 | 8 |
| Oct 6, 2007 | Day | 1-2-6 | 9 | 9 |