The winning Connecticut Play3 numbers for October 2, 2007 were: day 7-2-4; night 3-4-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 2, 2007 | Night | 3-4-9 | 16 | 7 |
| Oct 2, 2007 | Day | 7-2-4 | 13 | 4 |
| Oct 1, 2007 | Night | 3-7-6 | 16 | 7 |
| Oct 1, 2007 | Day | 4-2-6 | 12 | 3 |
| Sep 30, 2007 | Night | 8-7-1 | 16 | 7 |
| Sep 30, 2007 | Day | 1-5-2 | 8 | 8 |
| Sep 29, 2007 | Night | 6-6-2 | 14 | 5 |
| Sep 29, 2007 | Day | 2-8-3 | 13 | 4 |
| Sep 28, 2007 | Night | 3-8-4 | 15 | 6 |
| Sep 28, 2007 | Day | 9-2-0 | 11 | 2 |
| Sep 27, 2007 | Night | 4-4-2 | 10 | 1 |
| Sep 27, 2007 | Day | 7-1-0 | 8 | 8 |
| Sep 26, 2007 | Night | 2-3-5 | 10 | 1 |
| Sep 26, 2007 | Day | 4-1-7 | 12 | 3 |