The winning Connecticut Play3 numbers for December 30, 2006 were: night 5-9-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 30, 2006 | Night | 5-9-3 | 17 | 8 |
| Dec 29, 2006 | Night | 5-0-1 | 6 | 6 |
| Dec 29, 2006 | Day | 7-1-9 | 17 | 8 |
| Dec 28, 2006 | Night | 1-9-1 | 11 | 2 |
| Dec 28, 2006 | Day | 5-5-2 | 12 | 3 |
| Dec 27, 2006 | Night | 4-2-0 | 6 | 6 |
| Dec 27, 2006 | Day | 4-9-7 | 20 | 2 |
| Dec 26, 2006 | Night | 0-4-1 | 5 | 5 |
| Dec 26, 2006 | Day | 0-1-6 | 7 | 7 |
| Dec 25, 2006 | Night | 8-9-2 | 19 | 1 |
| Dec 25, 2006 | Day | 8-7-2 | 17 | 8 |
| Dec 24, 2006 | Night | 2-9-7 | 18 | 9 |