The winning Connecticut Play3 numbers for December 17, 2006 were: night 7-0-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 17, 2006 | Night | 7-0-9 | 16 | 7 |
| Dec 16, 2006 | Night | 1-9-6 | 16 | 7 |
| Dec 15, 2006 | Night | 5-5-1 | 11 | 2 |
| Dec 15, 2006 | Day | 8-8-7 | 23 | 5 |
| Dec 14, 2006 | Night | 8-3-6 | 17 | 8 |
| Dec 14, 2006 | Day | 9-1-9 | 19 | 1 |
| Dec 13, 2006 | Night | 5-3-1 | 9 | 9 |
| Dec 13, 2006 | Day | 3-0-6 | 9 | 9 |
| Dec 12, 2006 | Night | 5-3-3 | 11 | 2 |
| Dec 12, 2006 | Day | 1-5-8 | 14 | 5 |
| Dec 11, 2006 | Night | 5-5-3 | 13 | 4 |
| Dec 11, 2006 | Day | 0-0-2 | 2 | 2 |