The winning Connecticut Play3 numbers for December 9, 2006 were: night 4-1-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 9, 2006 | Night | 4-1-9 | 14 | 5 |
| Dec 8, 2006 | Night | 6-6-9 | 21 | 3 |
| Dec 8, 2006 | Day | 0-4-6 | 10 | 1 |
| Dec 7, 2006 | Night | 6-9-7 | 22 | 4 |
| Dec 7, 2006 | Day | 3-5-3 | 11 | 2 |
| Dec 6, 2006 | Night | 3-2-2 | 7 | 7 |
| Dec 6, 2006 | Day | 6-6-9 | 21 | 3 |
| Dec 5, 2006 | Night | 0-9-1 | 10 | 1 |
| Dec 5, 2006 | Day | 8-2-1 | 11 | 2 |
| Dec 4, 2006 | Night | 5-3-9 | 17 | 8 |
| Dec 4, 2006 | Day | 6-2-8 | 16 | 7 |
| Dec 3, 2006 | Night | 6-8-3 | 17 | 8 |