The winning Connecticut Play3 numbers for December 3, 2006 were: night 6-8-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 3, 2006 | Night | 6-8-3 | 17 | 8 |
| Dec 2, 2006 | Night | 6-5-4 | 15 | 6 |
| Dec 1, 2006 | Night | 5-9-6 | 20 | 2 |
| Dec 1, 2006 | Day | 9-7-2 | 18 | 9 |
| Nov 30, 2006 | Night | 6-4-2 | 12 | 3 |
| Nov 30, 2006 | Day | 0-9-7 | 16 | 7 |
| Nov 29, 2006 | Night | 4-6-4 | 14 | 5 |
| Nov 29, 2006 | Day | 7-1-1 | 9 | 9 |
| Nov 28, 2006 | Night | 5-0-3 | 8 | 8 |
| Nov 28, 2006 | Day | 0-4-2 | 6 | 6 |
| Nov 27, 2006 | Night | 0-8-6 | 14 | 5 |
| Nov 27, 2006 | Day | 6-7-1 | 14 | 5 |