The winning Connecticut Play3 numbers for October 15, 2006 were: night 8-0-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 15, 2006 | Night | 8-0-7 | 15 | 6 |
| Oct 14, 2006 | Night | 3-6-1 | 10 | 1 |
| Oct 13, 2006 | Night | 9-4-7 | 20 | 2 |
| Oct 13, 2006 | Day | 4-3-8 | 15 | 6 |
| Oct 12, 2006 | Night | 2-3-6 | 11 | 2 |
| Oct 12, 2006 | Day | 8-0-7 | 15 | 6 |
| Oct 11, 2006 | Night | 7-8-7 | 22 | 4 |
| Oct 11, 2006 | Day | 8-8-0 | 16 | 7 |
| Oct 10, 2006 | Night | 2-6-3 | 11 | 2 |
| Oct 10, 2006 | Day | 4-0-6 | 10 | 1 |
| Oct 9, 2006 | Night | 9-5-1 | 15 | 6 |
| Oct 9, 2006 | Day | 9-9-8 | 26 | 8 |