The winning Connecticut Play3 numbers for March 4, 2006 were: night 3-0-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 4, 2006 | Night | 3-0-0 | 3 | 3 |
| Mar 3, 2006 | Night | 9-8-0 | 17 | 8 |
| Mar 3, 2006 | Day | 8-4-5 | 17 | 8 |
| Mar 2, 2006 | Night | 4-1-1 | 6 | 6 |
| Mar 2, 2006 | Day | 0-5-4 | 9 | 9 |
| Mar 1, 2006 | Night | 0-6-5 | 11 | 2 |
| Mar 1, 2006 | Day | 9-0-4 | 13 | 4 |
| Feb 28, 2006 | Night | 3-1-2 | 6 | 6 |
| Feb 28, 2006 | Day | 3-9-7 | 19 | 1 |
| Feb 27, 2006 | Night | 3-7-0 | 10 | 1 |
| Feb 27, 2006 | Day | 2-5-9 | 16 | 7 |
| Feb 26, 2006 | Night | 7-5-2 | 14 | 5 |