The winning Connecticut Play3 numbers for December 31, 2005 were: night 3-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 31, 2005 | Night | 3-7-0 | 10 | 1 |
| Dec 30, 2005 | Night | 0-8-7 | 15 | 6 |
| Dec 30, 2005 | Day | 0-2-8 | 10 | 1 |
| Dec 29, 2005 | Night | 9-2-5 | 16 | 7 |
| Dec 29, 2005 | Day | 1-6-7 | 14 | 5 |
| Dec 28, 2005 | Night | 5-6-6 | 17 | 8 |
| Dec 28, 2005 | Day | 6-1-1 | 8 | 8 |
| Dec 27, 2005 | Night | 3-5-5 | 13 | 4 |
| Dec 27, 2005 | Day | 0-3-6 | 9 | 9 |
| Dec 26, 2005 | Night | 3-3-8 | 14 | 5 |
| Dec 26, 2005 | Day | 6-0-8 | 14 | 5 |
| Dec 25, 2005 | Night | 3-2-3 | 8 | 8 |