The winning Connecticut Play3 numbers for December 10, 2005 were: night 0-7-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 10, 2005 | Night | 0-7-3 | 10 | 1 |
| Dec 9, 2005 | Night | 0-4-2 | 6 | 6 |
| Dec 9, 2005 | Day | 9-6-4 | 19 | 1 |
| Dec 8, 2005 | Night | 1-5-1 | 7 | 7 |
| Dec 8, 2005 | Day | 5-4-9 | 18 | 9 |
| Dec 7, 2005 | Night | 7-1-1 | 9 | 9 |
| Dec 7, 2005 | Day | 2-6-3 | 11 | 2 |
| Dec 6, 2005 | Night | 0-1-5 | 6 | 6 |
| Dec 6, 2005 | Day | 6-8-8 | 22 | 4 |
| Dec 5, 2005 | Night | 9-3-5 | 17 | 8 |
| Dec 5, 2005 | Day | 4-6-9 | 19 | 1 |
| Dec 4, 2005 | Night | 9-3-7 | 19 | 1 |