The winning Connecticut Play3 numbers for December 3, 2005 were: night 7-2-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 3, 2005 | Night | 7-2-0 | 9 | 9 |
| Dec 2, 2005 | Night | 4-1-5 | 10 | 1 |
| Dec 2, 2005 | Day | 8-1-3 | 12 | 3 |
| Dec 1, 2005 | Night | 0-1-0 | 1 | 1 |
| Dec 1, 2005 | Day | 4-2-1 | 7 | 7 |
| Nov 30, 2005 | Night | 0-5-0 | 5 | 5 |
| Nov 30, 2005 | Day | 9-4-1 | 14 | 5 |
| Nov 29, 2005 | Night | 7-9-1 | 17 | 8 |
| Nov 29, 2005 | Day | 7-8-8 | 23 | 5 |
| Nov 28, 2005 | Night | 0-2-9 | 11 | 2 |
| Nov 28, 2005 | Day | 5-9-7 | 21 | 3 |
| Nov 27, 2005 | Night | 4-3-6 | 13 | 4 |