The winning Connecticut Play3 numbers for October 8, 2005 were: night 8-0-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 8, 2005 | Night | 8-0-2 | 10 | 1 |
| Oct 7, 2005 | Night | 1-3-8 | 12 | 3 |
| Oct 7, 2005 | Day | 4-3-9 | 16 | 7 |
| Oct 6, 2005 | Night | 0-5-6 | 11 | 2 |
| Oct 6, 2005 | Day | 1-2-3 | 6 | 6 |
| Oct 5, 2005 | Night | 6-6-5 | 17 | 8 |
| Oct 5, 2005 | Day | 1-1-1 | 3 | 3 |
| Oct 4, 2005 | Night | 5-2-7 | 14 | 5 |
| Oct 4, 2005 | Day | 5-6-1 | 12 | 3 |
| Oct 3, 2005 | Night | 2-9-5 | 16 | 7 |
| Oct 3, 2005 | Day | 7-3-8 | 18 | 9 |
| Oct 2, 2005 | Night | 9-6-1 | 16 | 7 |