The winning Connecticut Play3 numbers for September 25, 2005 were: night 3-9-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 25, 2005 | Night | 3-9-0 | 12 | 3 |
| Sep 24, 2005 | Night | 9-9-1 | 19 | 1 |
| Sep 23, 2005 | Night | 0-3-5 | 8 | 8 |
| Sep 23, 2005 | Day | 1-7-1 | 9 | 9 |
| Sep 22, 2005 | Night | 3-6-5 | 14 | 5 |
| Sep 22, 2005 | Day | 1-1-9 | 11 | 2 |
| Sep 21, 2005 | Night | 7-2-2 | 11 | 2 |
| Sep 21, 2005 | Day | 3-1-8 | 12 | 3 |
| Sep 20, 2005 | Night | 6-8-2 | 16 | 7 |
| Sep 20, 2005 | Day | 1-7-3 | 11 | 2 |
| Sep 19, 2005 | Night | 4-7-4 | 15 | 6 |
| Sep 19, 2005 | Day | 9-0-3 | 12 | 3 |