The winning Connecticut Play3 numbers for September 10, 2005 were: night 6-7-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 10, 2005 | Night | 6-7-1 | 14 | 5 |
| Sep 9, 2005 | Night | 1-1-9 | 11 | 2 |
| Sep 9, 2005 | Day | 4-4-8 | 16 | 7 |
| Sep 8, 2005 | Night | 7-4-8 | 19 | 1 |
| Sep 8, 2005 | Day | 9-1-5 | 15 | 6 |
| Sep 7, 2005 | Night | 6-8-5 | 19 | 1 |
| Sep 7, 2005 | Day | 0-8-3 | 11 | 2 |
| Sep 6, 2005 | Night | 3-9-1 | 13 | 4 |
| Sep 6, 2005 | Day | 6-6-1 | 13 | 4 |
| Sep 5, 2005 | Night | 7-5-8 | 20 | 2 |
| Sep 5, 2005 | Day | 8-8-0 | 16 | 7 |
| Sep 4, 2005 | Night | 7-6-5 | 18 | 9 |